In ΔABC, an exterior angle at B is represented by 4x−2. If the three non-adjacent interior angles are represented by x,2+x and 6+3x. Find the interior and exterior angle.
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Solution
Interior angle: sum of the angles inside =1800 x+2+x+6+3x=180 5x+8=180 5x=180−8 5x=172 x=34.4 The exterior angle is equal to the sum of the two non-adjacent interior angles. x+4x−2=180o (sum of adjacent angles forming a straight line) 5x=180−2 5x=178 x=35.6⇒ Exterior angle