Question

Question 11
In $\Delta ABC$ and DEF, AB =FD and $\angle A=\angle D$. The two triangles will be congruent by SAS axiom, if
(A) BC = EF
(B) AC = DE
(C) AC = EF
(D) BC = DE

Answer 1

Given in $\Delta ABC$ and $\Delta DEF$, AB = DF and $\angle A=\angle D$
We know that, tow triangles will be congruent by ASA rule, if two angles and the included side of one triangle are equal to the two angles and the included side of other triangle
$\therefore AC=DE$.