$I n Δ A B C a n d Δ D E F, it is given that ∠ B = ∠ E a n d ∠ C = ∠ F . In order that Δ A B C ≅ Δ D E F, we must have (a) A B = D F (b) A C = D E (c) B C = E F (d) ∠ A = ∠ D$

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Solution

In order for △ABC≅△DEF, we must have BC = EF.
Hence, the correct answer is the option (c).

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$I n Δ A B C a n d Δ D E F, it is given that AB = DE and BC = EF. In order that Δ A B C ≅ Δ D E F, we must have (a) ∠ A = ∠ D (b) ∠ B = ∠ E (c) ∠ C = ∠ F (d) none of these$

Q. In ∆ABC and ∆DEF, it is given that ∠B = ∠E and ∠C = ∠F. In order that ∆ABC ≅ ∆DEF, we must have
(a) AB = DF
(b) AC = DE
(c) BC = EF
(d) ∠A = ∠D

Q. In ∆ABC and ∆DEF, it is given that AB = DE and BC = EF. In order that ∆ABC ≅ ∆DEF, we must have
(a) ∠A = ∠D
(b) ∠B = ∠E
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Q. Question 11 (vi)
In

Δ A B C

and

Δ D E F

, AB=DE, AB || DE, BC =EF and BC ⃦EF. Vertices A, B and C are joined to vertices D, E and F respectively ( see the given figure). Show that

Δ A B C ≅ Δ D E F

In ∆ABC and ∆DEF, AB = DF and ∠A = ∠D. The two triangles will be congruent by SAS axiom if:

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In ΔABC and ΔDEF ,it is given that ∠B=∠E and ∠C=∠F. In order that ΔABC≅ ΔDEF, we must have(a) AB=DF (b) AC=DE (c) BC=EF (d) ∠A=∠D

In order for △ABC≅△DEF, we must have BC = EF. Hence, the correct answer is the option (c).

$I n Δ A B C a n d Δ D E F, it is given that ∠ B = ∠ E a n d ∠ C = ∠ F . In order that Δ A B C ≅ Δ D E F, we must have (a) A B = D F (b) A C = D E (c) B C = E F (d) ∠ A = ∠ D$

In order for △ABC≅△DEF, we must have BC = EF.
Hence, the correct answer is the option (c).