In $Δ A B C a n d Δ P Q R$ , $A B = 4 c m, B C = 5 c m, A C = 6 c m$ and $P Q = 4 c m, Q R = 5 c m, P R = 6 c m$ , then which of the following is true?

ΔABC≅ΔRQP

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ΔABC≅ΔQRP

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ΔABC≅ΔPQR

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ΔBAC≅ΔPQR

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Solution

The correct option is C
ΔABC≅ΔPQR

Since,

In $Δ A B C a n d Δ P Q R$

$A B = P Q = 4 c m$ , (Given)

$B C = Q R = 5 c m$ , (Given)

$A C = P R = 6 c m$ ; (Given)

Hence, $Δ A B C ≅ Δ P Q R$ , since for two congruent triangles, corresponding sides and corresponding angles are equal.

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Similar questions

In $Δ A B C$ , AB = 4 cm, BC = 5 cm, AC = 6 cm. In $Δ P Q R$ , PQ = 4 cm, QR = 5 cm, PR = 6 cm. Which of the following is true?

In ΔABC and PQR, AB=QR, BC=RP, AC=QP. So,

Question 73

State whether the statement is True or False.

In $Δ A B C$ , AB = 3.5 cm, AC = 5 cm, BC = 6 cm and in $Δ P Q R$ , PR = 3.5 cm, PQ = 5 cm, RQ = 6 cm. Then, $Δ A B C ≅ Δ P Q R$

Δ A B C a n d Δ P Q R, \frac{A B}{Q R} = \frac{B C}{P R} = \frac{C A}{P Q}

Δ P Q R \sim Δ C A B

Δ P Q R \sim Δ A B C

Δ C B A \sim Δ P Q R

Δ B C A \sim Δ P Q R

Δ A B C a n d Δ P Q R, \frac{A B}{Q R} = \frac{B C}{P R} = \frac{C A}{P Q}

Δ P Q R \sim Δ C A B

Δ P Q R \sim Δ A B C

Δ C B A \sim Δ P Q R

Δ B C A \sim Δ P Q R

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