Question

In $\Delta ABC,\angle A={100}^0,\angle B={30}^0$ and $\angle C={50}^0$ then

• A. $AB>AC$
• B. $AB<AC$
• C. $BC<AC$
• D. none of these

Answer 1

The correct option is A $AB>AC$

We know that the side opposite to largest angle is longest side of triangle .

$\angle A$ is the largest angle and side opposite to it is $BC$

So $BC$ is the longest side.

Then comes $\angle C$ and side opposite to it is $AB$.

So $AB$ is second longest side.

Then comes $\angle B$ and side opposite to it is $AC$.

So it is the smallest side.

So the decreasing order of side is

$BC>AB>AC$

So option $A$ is correct.