Question

In $\Delta$ ABC $\angle A={40}^o$ and $\angle B={60}^o$. The longest side of triangle ABC is AB.

• A. True
• B. False

Answer 1

The correct option is A True

sum of angles of a triangle=${180}^{\circ }$

$\therefore \angle A+\angle B+\angle C={180}^{\circ }$

$=>40+60+\angle C={180}^{\circ }$

$=>\angle C={80}^{\circ }$

side opposite largest angle is the largest side.

$\therefore$ side opposite$\angle C$ i.e.,AB is largest.

$\therefore A)True.$