Question

In $\Delta ABC,\angle A={40}^o,\angle B={80}^o$ find the shortest side of $\Delta ABC$ is BC.(Enter 1 if true or 0 otherwise)

Answer 1

In $△ABC$,
$\angle A+\angle B+\angle C=180$
$40+80+\angle C=180$
$\angle C=60$
In a triangle the shortest side is opposite to the shortest angle. Hence, BC is the shortest side.