Question

In $\Delta ABC,\angle B={30}^{\circ },\angle C={80}^{\circ }$ and $\angle A={70}^{\circ }$ then,

• A. $AB>BC<AC$
• B. $AB<BC>AC$
• C. $AB>BC>AC$
• D. $AB<BC<AC$

Answer 1

Answer: (C)

$AB>BC>AC$

In any triangle side opposite to the largest angle is the longest side.

Here $\angle C$ is largest and side opposite to it is $AB$

$\therefore AB$ is the longest side.

Then comes $\angle A$ and side opposite to it is $BC$.

$\therefore BC$ is second longest.

Then comes $\angle B$ and side opposite to it is $AC$

So it is the smallest side.

So the decreasing order of sides is

$AB>BC>AC$