Question

In $\Delta ABC,\angle B={45}^o,\angle C={55}^o$ and bisector of $\angle A$ meets BC at a point D. Find the $\angle ADB$ and $\angle ADC$.

• A. $\angle ADB={95}^o$
• B. $\angle ADC={85}^o$
• C. $\angle ADC={95}^o$
  
• D. $\angle ADB={85}^o$

Answer 1

Answer: (A), (B)

The correct options are
A $\angle ADB={95}^o$
B $\angle ADC={85}^o$

Given $\angle B=45,\angle C=55$

So, $\angle A=180°-45°-55°$

$=80°$

From $△ABD,40°+45°+\angle ADB=180°$

$⟹\angle ADB=95°$

From$△ADC,40°+55°+\angle ADC=180°$

$⟹\angle ADC=85°$.