In - ABC- - B- 900- AB- y units- BC- -3 units- AC- 2 units and angle A- x0- thenfind the value of y

sin x^∘ = sin A = BC/AC = √(3)/2 sin x = √(3)/2 sin x = sin 60 x = 60^∘ Now, cos x = cos 60 = 1/2 cos x = AB/AC 1/2 = y/2 ...

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Relationship between Trigonometric Ratios

In Δ ABC, ∠...

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In $Δ A B C, ∠ B = 90^{0}, A B = y u n i t s, B C = \sqrt{3} u n i t s, A C = 2 u n i t s$ and angle $A = x^{0}$ , then
find the value of $y$

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