In $Δ$ ABC, $∠ B = 90^{o}, A B = 8 c m$ and $B C = 6 c m .$ The length of the median $B M$ is:

3 c m

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5 c m

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4 c m

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7 c m

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Solution

The correct option is C $5 c m$
$A C^{2} = A B^{2} + B C^{2}$ (because $∠ B = 90^{o}$ )
$= 64 + 36 = 100$
$∴ A C = 10$
In a right triangle, the median from the right angle to the hypotenuse is half the length of the hypotenuse.
So, $B M = \frac{1}{2} A C = \frac{10}{2} = 5 c m .$

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In ΔABC, ∠B=90o,AB=8 cm and BC=6 cm. The length of the median BM is:

The correct option is C 5 cmAC2=AB2+BC2 (because ∠B=90o)=64+36=100∴AC=10In a right triangle, the median from the right angle to the hypotenuse is half the length of the hypotenuse. So, BM=12AC=102=5 cm.

In $Δ$ ABC, $∠ B = 90^{o}, A B = 8 c m$ and $B C = 6 c m .$ The length of the median $B M$ is:

The correct option is C $5 c m$
$A C^{2} = A B^{2} + B C^{2}$ (because $∠ B = 90^{o}$ )
$= 64 + 36 = 100$
$∴ A C = 10$
In a right triangle, the median from the right angle to the hypotenuse is half the length of the hypotenuse.
So, $B M = \frac{1}{2} A C = \frac{10}{2} = 5 c m .$