wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question


In ΔABC, B is a right angle, and BD is perpendicular to AC and DE is perpendicular to BC. Then AD.DC =

A
BD2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
BE.BC
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
AB.BC
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
BD.DC
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct options are
A BD2
B BE.BC
In ΔABD and ΔBDCADB=BDC=90A=DBC (Since in ΔBDC,DBC=90C=A and In ΔABCA=90C)Therefore,ΔADBΔBDC by AA similarityADDB=BDDC=ABBCBD2=AD.DCSimilarly ΔBDCΔBEDDBC=DBE (Common angle)BDC=DEB = 90BDBE=DCED=BCBDBD2=BE.BCBD2=AD.DC=BE.BC

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Pythagoras Theorem
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon