In - ABC- c cos A - - - - cos C - - -

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Sine Rule

In Δ ABC, c c...

Question

In $Δ A B C, c c o s (A - α) + α c o s (C + α) =$

$α c o s α$

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$b c o s α$

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$c c o s α$

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$2 b c o s α$

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Solution

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Similar questions

In $Δ A B C, c c o s (A - α) + α c o s (C + α) =$

α, β, γ

Δ A B C

\frac{cos A}{α} + \frac{cos B}{β} + \frac{cos C}{γ} =

\frac{b + c}{11} = \frac{c + a}{12} = \frac{a + b}{13}

Δ A B C

\frac{c o s A}{α} = \frac{c o s B}{β} = \frac{c o s C}{γ}

(α, β, γ)

\frac{b + c}{11} = \frac{c + a}{12} = \frac{a + b}{13}

Δ A B C

\frac{cos A}{α} = \frac{cos B}{β} = \frac{cos C}{γ}

(α, β, γ)

A (c o s α, s i n α), B (sin α, - c o s α), C (1, 2)

Δ A B C

α

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