In - ABC- cot A-2-cot B-2-cot C-2 is equal to

The correct option is A Δ/r^2 cot A / 2 +cot B / 2 +cot C / 2 nbsp;=√( s(s a) / (s b)(s c) nbsp;) +√( s(s b) / (s a)(s c) nbsp;) +√( s(s ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Substitution Method to Remove Indeterminate Form

In Δ ABC, ...

Question

In $Δ A B C,$ $c o t \frac{A}{2} + c o t \frac{B}{2} + c o t \frac{C}{2}$ is equal to

\frac{Δ}{r^{2}}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

\frac{(a + b + c)^{2}}{a b c} 2 R

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{Δ}{r}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{Δ}{R r}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

Suggest Corrections

Similar questions

Δ

A B C

A, B, C

a, b, c

a^{2} + c^{2} = 2002 b^{2}

\frac{c o t A + c o t C}{c o t B}

Δ

(c o t \frac{a}{2} + c o t \frac{b}{2})

(a s i n^{2} \frac{b}{2} + b s i n^{2} \frac{A}{2})

Δ A B C, Δ = a^{2} - (b - c)^{2}

tan \frac{A}{2} = \frac{1}{2}

Δ A B C, cot \frac{A}{2} = \frac{Δ}{(s - b) (s - c)}

Δ A B C

b^{2} + c^{2} = 2 a^{2}

\frac{c o t A}{c o t B + c o t C}

Δ = a^{2} - {(b - c)}^{2}

Δ

Δ A B C

tan A

Join BYJU'S Learning Program