In ΔABC, D is a point on AB and E is a point on AC. If ADDB=AEEC and ∠ADE = ∠ACB, then ΔABC is_____ triangle.
A
an equilateral
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B
an isosceles
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C
a right angled
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D
a scalene
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Solution
The correct option is B an isosceles From Converse of Basic Proportionality theorem, Since ADDB=AEEC,DE∥BC. Given ∠ ADE = ∠ ACB ---- (1) Also ∠ ADE = ∠ ABC -----(2) (Transverse angles in parallel lines are equal) From (1) & (2), ⇒∠ABC=∠ACB Hence it is an "isosceles triangle".