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Question

In Δ ABC, DE is parallel to BC. Prove that area of ∆DOB= area of ∆EOC.


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Solution

Area of ∆BEC and ∆BDC will be equal as they are on the same base and between same parallel.
Also, Area of ∆BEC - Area of ∆BOC = Area of ∆BDC - Area of ∆BOC.
Thus, Area of ∆DOB = Area of ∆EOC.


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