It is given that, In ΔABC and DE∥BC.
We have to find AD=?
Since,
DB=7.2c.m.
AE=1.8c.m.
EC=5.4c.m.
So, We know that (using Thales Theorem)
ADDB=AECE
Then,
AD7.2=1.85.4
AD=1.8×7.25.4
AD=7.23
AD=2.4 c.m.
Hence it is complete solution.
In a triangle ABC and DE parallel to BC , if AD= 1.5, AE=1cm and DB =3cm, find EC