In - ABC- b-cr1-c-a r2-a-br3-

Nbsp; b cr_1+c a r_2+a br_3 =(b c)(s a) Δ+(c a)(s b) Δ+(a b)(s c) Δ =1Δ[bs ab cs+ac+cs bc as+ab+as ac bs+bc]=0 ⇒b cr_1+c a r_2+a br_3=0 nbsp; ...

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Ex Radius

In Δ ABC, b-c...

Question

In $Δ A B C, \frac{b - c}{r_{1}} + \frac{c - a}{r_{2}} + \frac{a - b}{r_{3}} =$

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Similar questions

Δ A B C

r_{1} = 8, r_{2} = 12, r_{3} = 24

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(a - b) (s - c) = (b - c) (s - a)

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a < b < c

r

r_{1}, r_{2}, r_{3}

A, B, C

r < r_{1} < r_{2} < r_{3}

△ A B C, r_{1} r_{2} + r_{2} r_{3} + r_{3} r_{1} = \frac{r_{1} r_{2} r_{3}}{r}

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Δ A B C

a = 18, b = 24, c = 30

l = r_{2} - r_{1}, m = r_{3} - r_{2}

n = r_{3} - r_{1}

l, m, n

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