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Question

In ΔABC, foot of the altitudes from vertices to the opposite sides are (0, 0) (3, 0) and (0, 4) then the orthocenter of ΔABC is

A
(0, 0)
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B
(3, 4)
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C
(4, 3)
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D
(1, 1)
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Solution

The correct option is D (1, 1)
The triangle formed by foot of altitudes is called pedal triangle. The in centre of pedal triangle is orthocenter of main triangle

Incentre of triangle formed by (0,0) (3,0) (0,4) is ortho centre of ΔABC
I=(ax1+bx2+cx3a+b+c,ay1+by2+cy3a+b+c)
=(1,1)
= orthocenter of ΔABC=(1,1)

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