In ΔABC, foot of the altitudes from vertices to the opposite sides are (0, 0) (3, 0) and (0, 4) then the orthocenter of ΔABC is
A
(0, 0)
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B
(3, 4)
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C
(4, 3)
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D
(1, 1)
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Solution
The correct option is D(1, 1) The triangle formed by foot of altitudes is called pedal triangle. The in centre of pedal triangle is orthocenter of main triangle ∴Incentre of triangle formed by (0,0) (3,0) (0,4) is ortho centre of ΔABC I=(ax1+bx2+cx3a+b+c,ay1+by2+cy3a+b+c) =(1,1) =∴ orthocenter of ΔABC=(1,1)