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Question

In ΔABC given below, AB = 10 cm, AC = 8 cm and A=45. The find the area of ΔABC.


A

102 cm2

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B

20 cm2

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C

202 cm2

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D

52 cm2

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Solution

The correct option is C

202 cm2


Since A=45 and D=90,

C=9045=45

In ADC,

cos 45=CDAC

12=CD8

CD=82=42 cm

Now, area of triangle ABC

=12×AB×CD

=12×10×42

=202 cm2


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