In ΔABC,if a=3,b=4,c=5,then sin 2B=
45
320
2425
150
cosB=9+25−162.3.5=182.3.5=35⇒sin B=45Therefore sin2B=2.45.35=2425.
If cos4A – sin4A = 35, then 2cos2A−1= ?