In ΔABC, if AD is a median, which of the following relations holds good?
AB+AC>2AD
Given - AD is a median of triangle ABC.
Let us extend AD to G such that AD=DG. B,G and C,G are joined.
Now:
In Δ ABD and Δ CGD:
1. AD = DG [by construction].
2. ∠ ADB = ∠ CDG (vertically opposite angles)
3. BD = DC (since AD is a median (given)
Therefore, Δ ABD ≅ Δ DGC (by S.A.S. congruency)
AB = CG [since they are corresponding sides of congruent triangles.]
Now In triangle ACG:
AC + CG > AG [since, sum of two sides of a triangle is greater than the third side.]
⇒ AC + AB > AD + DG [since, AB=CG ( proved earlier )]
⇒ AB + AC > AD + AD [since, AD=DG (by construction)]
⇒ AB + AC > 2AD.