Question

In $\Delta ABC$, if $\angle A+\angle B={90}^{\circ }$, cot $B=\frac{3}{4}$, then the value of $\tan A$ is :

• A. $\frac{4}{5}$
• B. $\frac{3}{4}$
• C. $\frac{4}{3}$
• D. $\frac{3}{5}$

Answer 1

The correct option is B $\frac{3}{4}$

$\angle A+\angle B={90}^{\circ }\angle B={90}^{\circ }-\angle A$

$\cot B=\frac{3}{4}\cot ({90}^{\circ }-\angle A)=\frac{3}{4}\tan A=\frac{3}{4}$