$I n Δ A B C, i f ∠ B = 76^{\circ} a n d ∠ C = 48^{\circ}, f i n d ∠ A .$

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Solution

Sum of angles in a triangle = 180

$∠ A + ∠ B + ∠ C = 180^{o} ∠ A = 180^{o} - 76^{o} - 48^{o} ∠ A = 56^{o}$

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Similar questions

△ A B C

∠ B = 76^{\circ}

∠ C = 48^{\circ}

∠ A

In $Δ A B C$ , if $∠ A + ∠ B = 125^{\circ}$ and $∠ A + ∠ C = 113^{\circ}$ , find $∠ A, ∠ B$ and $∠ C$ .

$I n Δ A B C, i f ∠ A + ∠ B = 108^{\circ} a n d ∠ B + ∠ C = 130^{\circ}, f i n d ∠ A, ∠ B a n d ∠ C .$

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