In - ABC- if b-c-3a then B2C2-

Given: b+c=3a ⇒ nbsp; a+b+c=4a⇒ s=2a We know, A2=s(s a)Δ ⇒B2C2=s(s b)s(s c)Δ^2 =ss a=2aa=2 ...

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Properties of Argument

In Δ ABC, if ...

Question

In $Δ A B C,$ if $b + c = 3 a$ then $cot \frac{B}{2} cot \frac{C}{2} =$

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Δ A B C

b + c = 3 a

cot \frac{B}{2} cot \frac{C}{2} = 2

Δ A B C

\frac{b + c}{a} = \frac{m}{n} (m > n

m, n

cot \frac{B}{2} cot \frac{C}{2} = \frac{m + n}{m - n}

Δ A B C, i f cos \frac{A}{2} = \sqrt{\frac{b + c}{2 c}},

Δ A B C,

A, B

C, cos (\frac{B + 2 C + 3 A}{2}) + cos (\frac{A - B}{2}) =

[\to a \to b \to c] = - 2

[\to a + 2 \to b, \to b - 2 \to c, \to c + 3 \to a] =

△ A B C, 3 a = b + c

cot \frac{B}{2} cot \frac{C}{2}

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