Question

In $\Delta$ ABC, if cot A + cot B + cot C = $\sqrt{3}$, then ABC is an

• A. Eequilateral triangle
• B. Right angled triangle
• C. Isosceles
• D. None

Answer 1

The correct option is A Eequilateral triangle

A = B = C = ${60}^{\circ }$ satisfies the equation cot A + cot B + cot C = $\sqrt{3}$ . $\therefore \Delta$ ABC is equilateral