Question

In $\Delta$ ABC, if D is a point on side AB such that $\frac{AB}{AD}=3$. Find $\frac{AD}{DB}$.

• A. $3$
• B. $\frac{1}{3}$
• C. $2$
• D. $\frac{1}{2}$

Answer 1

The correct option is D $\frac{1}{2}$

$\frac{AB}{AD}=3\Rightarrow \frac{AD+DB}{AD}=3\Rightarrow 1+\frac{DB}{AD}=3\Rightarrow \frac{DB}{AD}=2\Rightarrow \frac{AD}{DB}=\frac{1}{2}$