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Question

In ΔABC, if cosAa=cosBb, then show that it is an isosceles triangle.

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Solution

cosAa=cosBb, ....(i)
sinAa=sinBb .........(ii) (True for any triangle)
Hence (2)(1)
tanA=tanB
A=B
So , ΔABC is isosceles as two angles are equal.

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