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Byju's Answer
Standard IX
Mathematics
Value of Standard Angle(30,60,90)
In Δ ABC, i...
Question
In
Δ
A
B
C
, if
sin
A
+
sin
B
+
sin
C
=
√
2
+
1
and
cos
A
+
cos
B
+
cos
C
=
√
2
,
then the triangle is
A
equilateral
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B
right angled
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C
isosceles
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D
right angled isosceles
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Solution
The correct option is
D
right angled isosceles
We can see that given condition can only be satisfied
when
A
=
B
=
45
o
and
C
=
90
o
which forms a Right Angled Isosceles triangle.
Therefore Answer is
D
Suggest Corrections
0
Similar questions
Q.
In
△
A
B
C
,
s
i
n
A
+
s
i
n
B
+
s
i
n
C
=
1
+
√
2
and
c
o
s
A
+
c
o
s
B
+
c
o
s
C
=
√
2
if the triangle is
Q.
If
cos
a
+
cos
b
+
cos
c
=
sin
a
+
sin
b
+
sin
c
=
0
then
cos
(
a
−
b
)
+
cos
(
b
−
c
)
+
cos
(
c
−
a
)
=
−
3
2
.
Q.
If
sin
A
+
sin
B
+
sin
C
=
0
and
cos
A
+
cos
B
+
cos
C
=
0
then
cos
(
A
+
B
)
+
cos
(
B
+
C
)
+
cos
(
C
+
A
)
=
Q.
Show that
cos
(
B
−
C
)
+
cos
(
C
−
A
)
+
cos
(
A
−
B
)
=
−
3
2
if and only if
cos
A
+
cos
B
+
cos
C
=
0
and
sin
A
+
sin
B
+
sin
C
=
0
Q.
If
A
+
B
+
C
=
π
and
cos
A
+
cos
B
+
cos
C
=
0
=
sin
A
+
sin
B
+
sin
C
then
cos
3
A
+
cos
3
B
+
cos
3
C
=
1
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