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Question

In ΔABC, if sinA+sinB+sinC=2+1 and cosA+cosB+cosC=2, then the triangle is

A
equilateral
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B
right angled
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C
isosceles
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D
right angled isosceles
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Solution

The correct option is D right angled isosceles
We can see that given condition can only be satisfied
when A=B=45o and C=90o

which forms a Right Angled Isosceles triangle.

Therefore Answer is D

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