Question

In $\Delta ABC$ it is given that $\angle A={65}^o$ and $\angle B={70}^o$. FInd $\angle C$.

Answer 1

Sum of all angle triangle $={180}^0$

$\begin{array}{c}\angle A+\angle B+\angle C={180}^0\\ ={180}^0-{65}^0-{70}^0={45}^0\end{array}$