In - ABC- m- B - 90 and ADBC- Also AB-9- BC-6 and BD-2 then find AC-

By Pythagoras theorem in Δ ADB , AB^2=BD^2+AD^2 ⇒ AD^2=AB^20 BD^2 Similarly in Δ ACD, AC^2=AD^2+DC^2 ⇒ AC^2=AB^2 BD^2+DC^2 =81 4+16 ...

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Classification of Triangles Based on Angles

In Δ ABC, m...

Question

In $Δ A B C, m ∠ B < 90$ and $¯ ¯¯¯¯¯¯¯ ¯ A D ⊥ ¯ ¯¯¯¯¯¯ ¯ B C$ . Also $A B = 9, B C = 6$ and $B D = 2$ then find $A C$ .

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