In - ABC- right angled at B- expressions for sec C and cosec C isA- AC - BC - AC - BCB- AC - AB - AC - ABC- AC-BC - AC-ABD- AC-AB- AC-BC

The correct option is C AC/BC , AC/AB Recall the trigonometric ratios sec C = hypotenuse/adjacent side and cosec C = hypotenuse/opposite side sec C = AC/BC an ...

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Standard X

Mathematics

Trigonometric Ratio(sin,cos,tan)

In Δ ABC, rig...

Question

In $Δ$ ABC, right angled at B, expressions for sec C and cosec C is

AC/BC , AC/AB

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AC/BC , AC/BC

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AC/AB , AC/AB

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AC/AB , AC/BC

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Solution

The correct option is A
AC/BC , AC/AB

Recall the trigonometric ratios

sec C = $\frac{h y p o t e n u s e}{a d j a c e n t s i d e}$ and cosec C = $\frac{h y p o t e n u s e}{o p p o s i t e s i d e}$

sec C = $\frac{A C}{B C}$ and cosec C = $\frac{A C}{A B}$

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Sum of

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and

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In Δ ABC, right angled at B, expressions for sec C and cosec C is

The correct option is A AC/BC , AC/AB Recall the trigonometric ratios sec C = hypotenuseadjacentside and cosec C = hypotenuseoppositeside sec C = ACBC and cosec C = ACAB

In $Δ$ ABC, right angled at B, expressions for sec C and cosec C is

The correct option is A
AC/BC , AC/AB

Recall the trigonometric ratios

sec C = $\frac{h y p o t e n u s e}{a d j a c e n t s i d e}$ and cosec C = $\frac{h y p o t e n u s e}{o p p o s i t e s i d e}$

sec C = $\frac{A C}{B C}$ and cosec C = $\frac{A C}{A B}$