Question

In $\Delta ABC$ seg $AD$ is median. If $AB=11,AC=17,BC=12$ then find the value of $AD$.

Answer 1

Given, $AB=11,AC=17$ and $BC=12$
According to Apollonius theorem,
$A{B}^2+A{C}^2=2A{D}^2+2B{D}^2$
$\therefore (11{)}^2+(17{)}^2=2A{D}^2+2(6{)}^2$
$\therefore 121+289-72=2A{D}^2$
$\therefore 338=2A{D}^2$
$169=A{D}^2$
$AD=13cm$.