$I n Δ A B C, AB = AC and ∠ B = 50^{\circ} . T h e n ∠ A = ? (a) 40^{\circ} (b) 50^{\circ} (c) 80^{\circ} (d) 130^{\circ}$

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Solution

ANSWER:
In △ABC, we have:
AB = AC
∠B = 50°
Since ABC is an isosceles triangle, we have:
∠C=∠B
∠C=50°
In triangle ABC, we have:
∠A+∠B+∠C=180°⇒∠A+50+50=180°⇒∠A=180°-100°∴∠A=80°
Hence, the correct answer is option (c).

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Δ A B C

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△ A B C

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In ΔABC, BC = AB and ∠B = 80°, then ∠A is equal to:

$I n Δ A B C, BC = AB and ∠ B = 80^{\circ} . T h e n, ∠ A = ? (a) 50^{\circ} (b) 40^{\circ} (c) 100^{\circ} (d) 80^{\circ}$

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