In Δ ABC, the bisector AX of ∠A intersects BC at X. XL ⊥ AB and XM ⊥ AC are drawn. Is XL = XM?
Yes, they are equal
We know that every point on the bisectors of the angle between two intersecting lines is equidistant from the intersecting lines.
Here, X lies on the bisector of ∠BAC. Therefore, X is equidistant from AB and AC.
It is given that XL ⊥ AB and XM ⊥ AC. Therefore, the distance of X from AB and AC are XL and XM respectively.
Hence, XL = XM.