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Question

In Δ ABC the sides opposite to angles A,B,C are denoted by a,b,c respectively.
The value of acosA+bcosB+ccosC is equal to?

A
2asinBsinC
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B
2bsinCsinA
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C
2csinAsinB
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D
None of the above
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Solution

The correct options are
A 2asinBsinC
B 2bsinCsinA
C 2csinAsinB
We know that according to Sine law;
asinA=asinB=csinC=2R
We have;
acosA+bcosB+ccosC
=2RsinA.cosA+2RsinB.cosB+2RsinC.cosC
=R(sin2A+sin2B+sin2C)
=R×4sinA.sinB.sinC
=2.(2RsinA)sinB.sinC=2asinB.sinC
=2.(2RsinB)sinA.sinC=2bsinA.sinC
=2.(2RsinC)sinA.sinB=2csinA.sinC

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