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Question

In ΔABC the value of sinA+sinBsinC=

A
a+bc
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B
a+cb
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C
c+ba
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D
none of these
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Solution

The correct option is A a+bc
In ΔABC we have,
a=2RsinA,b=2RsinB,c=2RsinC.
Then,
sinA+sinBsinC
=a2R+b2Rc2R
=a+bc.

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