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Question

In ΔABC; with usual notations, if cosA=sinBsinC, then the triangle is _______.

A
Acute angled triangle
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B
Equilateral triangle
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C
Obtuse angled triangle
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D
Right angled triangle
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Solution

The correct option is D Right angled triangle
We know that 2RSinB=b=AC and 2RSinC=c=AB
Thus, cosA=ACAB .
Using above relation we can claim that ABC is a right angled triangle with AB as hypotenuse ,right angled at C.

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