Question

In $\Delta$ ABD, AB=AD and AC is perpendicular to BD. State the property by which $\Delta$ ACB $\cong$ $\Delta$ ACD.

• A. SAS property
• B. SSS property
• C. RHS property
• D. ASA property

Answer 1

The correct option is C

RHS property

$\text{In the given triangle,}AB=AD\text{(Given)}AC\text{is the common side}\angle ACB=\angle ACD={90}^{\circ }.$

Hence, by RHS congruence rule, the two triangles are congruent.