In - G-177 K cal for 1 2 Fes-32O2g- Fe2O3s and - G-19K cal for 2 4 Fe2O3s-Fes- 3Fe3O4sWhat is the Gibbs free energy of formation of Fe3O4-

The correct option is D 727kcalmol 2Fe(s)+3/2O_2(g)→ Fe_2O_3(s) #160; #160; #160; #160; #160; #160; #160; (1)Multiply equation ( ...

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Calorimetry

In Δ G=-177...

Question

In $Δ G = - 177$ K cal for
$(1)$ $2 F e (s) + \frac{3}{2} O_{2} (g) \to F e_{2} O_{3} (s)$ and $Δ G = - 19$ K cal for
$(2)$ $4 F e_{2} O_{3} (s) + F e (s) \to 3 F e_{3} O_{4} (s)$
What is the Gibbs free energy of formation of $F e_{3} O_{4}$ ?

+ 229.6 \frac{k c a l}{m o l}

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- 242.3 \frac{k c a l}{m o l}

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- 727 \frac{k c a l}{m o l}

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- 229.6 \frac{k c a l}{m o l}

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Δ G = - 177 k cal

2 F e (s) + \frac{3}{2} O_{2} (g) \to F e_{2} O_{3} (s)

Δ G = - 19 k cal

4 F e_{2} O_{3} (s) + F e (s) \to 3 F e_{3} O_{4} (s)

F e_{3} O_{4} (s)

$Δ G = - 177 K c a l$ for $2 F e (s) + \frac{3}{2} O_{2} (g) \to F e_{2} O_{3} (s)$ and

What is the Gibbs free energy of formation of $F e_{3} O_{4}$ ?;

Δ G = - 177 K c a l

2 F e (s) + \frac{3}{2} O_{2} (g) \to F e_{2} O_{3} (s)

Δ G = - 19 K

4 F e_{2} O_{3} (s) + F e (s) \to 3 F e_{3} O_{4} (s)

F e_{3} O_{4}

Δ G = - 177 k cal

2 F e (s) + \frac{3}{2} O_{2} (g) \to F e_{2} O_{3} (s)

Δ G = - 19 k cal

4 F e_{2} O_{3} (s) + F e (s) \to 3 F e_{3} O_{4} (s)

F e_{3} O_{4} (s)

Δ G = - 177

2 F e (s) + \frac{3}{2} O_{2} (g) \to F e_{2} O_{3} (s)

Δ G = - 19 K c a l

4 F e_{2} O_{3} (s) + F e (s) \to 3 F e_{3} O_{4} (s)

F e_{3} O_{4} (s)

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