Question

In $\Delta PQR,\angle P=2\angle Q$ and$\angle R=3\angle Q$, calculate the angles of $\Delta PQR$

Answer 1

Given,

$\angle P=2\angle Q$

$\angle R=3\angle Q$

We know that in $△PQR$

$\angle P+\angle Q+\angle R=180$

$2\angle Q+\angle Q+3\angle Q=180$

$6\angle Q=180$

$\angle Q=\frac{180}{6}={30}^0$

$\angle P=2\angle Q={60}^0$

$\angle R=3\angle Q={90}^0$