Question

In $\Delta$PQR, $\angle$P$={70}^o$, $\angle$Q$={65}^o$, then find $\angle$R.

Answer 1

According to angle sum property of triangle

$\angle P+\angle Q+\angle R={180}^o$

${70}^o+{65}^o+\angle R={180}^o$

$\therefore \angle R={45}^o$

$\therefore$ Measure of $\angle R={45}^o$