Question

In $\Delta PQR,\angle Q={90}^{\circ }$ and $QS$ is the median. If $QS=7.4$ cm, then $PR$ is:

• A. $7.4$ cm
• B. $54.76$ cm
• C. $3.7$ cm
• D. $14.8$ cm

Answer 1

The correct option is D $14.8$ cm

In the right triangle the median drawn to the hypotenuse divides the triangle in two isosceles triangles.
$\Delta PQS\cong \Delta RQS$
Also,

$QS=PS=RS$
So, $PR=PS+RS=QS+QS=2QS=2\times 7.4$ cm $=14.8$ cm