In - PQR- if - R - - Q- then A QR - PR B PQ - PR C PQ - PR D QR - PR

Name: EXEMP - Grade 09 - Mathematics - Lines and Angles - Q9
Uploaded: 2022-07-04T10:36:42+05:30
Description: Given ∠ R gt; ∠ Q ⇒ PQ gt; PR [side opposite to greater angle is longer] ...

Given ∠ R gt; ∠ Q ⇒ PQ gt; PR [side opposite to greater angle is longer] ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard IX

Mathematics

Relationship between Unequal Sides of Triangle and the Angles Opposite to It.

In Δ PQR, if ...

Question

Question 9
In $Δ P Q R$ , if $∠ R > ∠ Q$ , then
(A) QR > PR
(B) PQ > PR
(C) PQ < PR
(D) QR < PR

Open in App

Solution

Given $∠ R > ∠ Q$

$\Rightarrow P Q > P R$ [side opposite to greater angle is longer]

Suggest Corrections

Similar questions

Question 9

In $Δ P Q R$ ,

a) PQ - QR > PR
b) PQ + QR < PR
c) PQ - QR < PR
d) PQ + PR < QR

Q. In ΔPQR, if

∠ R > ∠ Q

, then

(a) QR > PR

(b) PQ > PR

(c) PQ < PR

(d) QR < PR

Choose the correct alternative answer for the following questions.

(i) If two sides of a triangle are 5 cm and 1.5 cm, the lenght of its third side cannot be . . . . . . . .

(A) 3.7 cm (B) 4.1 cm (C) 3.8 cm (D) 3.4 cm

(ii) In

∆

PQR, If

∠

R >

∠

Q then . . . . . . . .

(A) QR > PR

(B) PQ > PR

(iii) In

∆

TPQ,

∠

T = 65^° ,

∠

P = 95^° which of the following is a true statement ?

(A) PQ < TP

(B) PQ < TQ
(C) TQ < TP < PQ

(D) PQ < TP < TQ

Q. Simplify:

(p q - q r + p r) (p q + q r) - (p r + p q) (p + q - r)

Q. A =

⎡ ⎢ ⎣ \begin{matrix} - q r & p (q + r) & p r + p q p q + q r & - p r & p q + q r q r + p r & q r + p r & - p q \end{matrix} ⎤ ⎥ ⎦

then

| A |

equals:

Join BYJU'S Learning Program

Explore more

Relationship between Unequal Sides of Triangle and the Angles Opposite to It.

Standard IX Mathematics

Join BYJU'S Learning Program

Question 9 In ΔPQR, if ∠R>∠Q, then (A) QR > PR (B) PQ > PR (C) PQ < PR (D) QR < PR

Given ∠R>∠Q ⇒PQ>PR [side opposite to greater angle is longer]

Question 9
In $Δ P Q R$ , if $∠ R > ∠ Q$ , then
(A) QR > PR
(B) PQ > PR
(C) PQ < PR
(D) QR < PR

Given $∠ R > ∠ Q$

$\Rightarrow P Q > P R$ [side opposite to greater angle is longer]