Question

In $\Delta PQR,PE$ is perpendicular bisector of $\angle QPR$, then :

• A. $QE=QR$
• B. $QP>QE$
• C. $PQ=PR$
• D. $PQ>PR$

Answer 1

The correct option is A $QE=QR$

In triangles $PEQ$ and $PER$

$PE=PE\left(common\right)$

$\angle PEQ=\angle PER$

$QE=RE$

Thus by ASA congruency, $△PEQ$ and $△PER$ are congruent.

By cpct, $PQ=PR$.