In - PQR- PS and RT are medians and SM - RT Then PQ -

The correct option is C 4 QMIt is given that #160; RT is the median of triangle PQR #160;Now in Δ QRT S is the midpoint of QR #160;and SM is parallel ...

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Standard IX

Mathematics

Application of Similarity

In Δ PQR, P...

Question

In $Δ P Q R$ , PS and RT are medians and SM || RT Then PQ =

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2 QM

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4 QM

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Solution

The correct option is C 4 QM
It is given that RT is the median of triangle PQR
Now in $Δ Q R T$
S is the midpoint of QR
and SM is parallel to TR
so by converse of midpoint theorem
M is the midpoint of TQ
$Hence QM= \frac{T Q}{2}$
$S o Q M = \frac{1}{2} \times \frac{1}{2} \times P Q$
$P Q = 4 Q M$

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In ΔPQR, PS and RT are medians and SM || RT Then PQ =

The correct option is C 4 QMIt is given that RT is the median of triangle PQR Now inΔQRT S is the midpoint of QR and SM is parallel to TR so by converse of midpoint theoremM is the midpoint of TQHence QM=TQ2 SoQM=12×12×PQ PQ=4QM

In $Δ P Q R$ , PS and RT are medians and SM || RT Then PQ =

The correct option is C 4 QM
It is given that RT is the median of triangle PQR
Now in $Δ Q R T$
S is the midpoint of QR
and SM is parallel to TR
so by converse of midpoint theorem
M is the midpoint of TQ
$Hence QM= \frac{T Q}{2}$
$S o Q M = \frac{1}{2} \times \frac{1}{2} \times P Q$
$P Q = 4 Q M$