Question

In $\Delta PQR,Q$ is a right angle, $PQ=3$ and $QR=4$. If $\angle P=\alpha$ and $\angle R=\beta$, then $\tan \beta$ is equal to

• A. $\frac{3}{4}$
• B. $\frac{4}{3}$
• C. $\frac{3}{5}$
• D. $\frac{5}{3}$

Answer 1

The correct option is A $\frac{3}{4}$

$PQ=3,QR=4$

Now, $\tan \beta =\frac{opposite}{hypotenuse}=\frac{PQ}{QR}=\frac{3}{4}$