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Question

In ΔPQR, side QR =10 cm and height PM = 4.4 cm: If PR = 11 cm, then altitude QN equals :

A
4 cm
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B
5 cm
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C
5.5 cm
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D
5.6 cm
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Solution

The correct option is A 4 cm

Area of triangle =12× base × height
For base QR=10cm, height PM=4.4cm.

So, area =12×10×4.4=22cm2

Let the altitude QN for base PR=11cm, be h.

Area of the triangle will be the same considering any side of the base and its corresponding height.
Hence, area =12×11×h=22cm2=>h=4cm


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