Question

In $\Delta PQR$, side QR =10 cm and height PM = 4.4 cm: If PR = 11 cm, then altitude QN equals :

• A. 4 cm
• B. 5 cm
• C. 5.5 cm
• D. 5.6 cm

Answer 1

The correct option is A 4 cm

Area of triangle $=\frac{1}{2}\times$ base $\times$ height
For base $QR=10cm$, height $PM=4.4cm$.

So, area $=\frac{1}{2}\times 10\times 4.4=22{cm}^2$

Let the altitude $QN$ for base $PR=11cm$, be h.

Area of the triangle will be the same considering any side of the base and its corresponding height.
Hence, area $=\frac{1}{2}\times 11\times h=22{cm}^2=>h=4cm$